How to compare list A and B and return yes if any sublist of B is in A

Assume there are two lists A=[[1,2,3],[4,5,6],[7,8,9],[10,11,12]] and B=[[1,2,3],[5,6,4],[7,1,9]]. I want to compare these two lists and return yes if any sub list of B is in A and if not return no. Also, I want 2nd sublist of B which is [5,6,4] returns yes since it has all items of 2nd sub list of A which is [4,5,6].

Therefore, output should be like below:

yes
yes
no

This is the code:

A=[[1,2,3],[4,5,6],[7,8,9],[10,11,12]]
B=[[1,2,3],[5,6,4],[7,1,9]] 
     
for i in range(len(B)):
    if B[i] in A:
        print('yes')
        
    else:
        print('no')