Guidance needed with using LIKE operator in If-Else block of a Snowflake Stored procedure

I'm trying to create a Snowflake stored procedure, similar to the below code. But the Like Operator in the If-Else block is not working. Please look at the Bold code below. ***

Urgent help appreciated

---

----- STORED PROCEDURE ------ 
create or replace procedure test_stored_procedure(inputvalue varchar)
returns string not null
language javascript
as 
$$
    **if (inputvalue like '%abc%') { return 'valid input' } else { return 'invalid input'}**
$$
 ; 

I am getting the below error while calling the procedure

JavaScript compilation error: Uncaught SyntaxError: Unexpected identifier in test_stored_procedure at ' if (inputvalue like '%abc%') { return 'valid input' } else { return 'invalid input'}' position 14