Why is my 2nd if statement in Java not working? [duplicate]

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• How do I compare strings in Java? 23 answers

Good morning!

The goal of my code is to generate all possible three character strings that include A-Z and 0-9. For example, I want all possibilities from AAA to 999.

Problem: My own code will only output up to A99. My 2nd if statement is not generating the next step, which is confounding me. I need the 2nd if statement to work so that the A in A99 will increase to BAA and keep going.

Here is my code:

{    
        public static void main(String args[]) {

        String[] AZ09 = {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"};

        while (z < AZ09.length) {
        System.out.println(AZ09[x]+AZ09[y]+AZ09[z]);
        z++;
        if (AZ09[z] == "9") {
            System.out.println(AZ09[x]+AZ09[y]+AZ09[z]);
            y++;
            z = 0;
        }
        if (AZ09[y] == "9" && AZ09[z] == "9") {
            System.out.println(AZ09[x]+AZ09[y]+AZ09[z]);
            x++;
            y = 0;
            z = 0;
        }
     }

Solution? Thoughts?

Please don't post as duplicate. I tried the .equals() method and still no dice

Thank you so much!