I have a bit of code that contains nested if statements:
if(numberOfNeighbors == 1){
//go through comparison again, add Pixel(i,j) to current linked list -> complist[numberOfComponents]
// break out of large check ??
if(ji.getPixelColor(i, j) == (ji.getPixelColor(i-1,j-1))){ //compare to top left
complist[numberOfComponents].addFirst(new Pixel(i,j,numberOfComponents)); break;
}
if(ji.getPixelColor(i, j) == (ji.getPixelColor(i,j-1))){ // compare to top
complist[numberOfComponents].addFirst(new Pixel(i,j,numberOfComponents)); break;
}
if(ji.getPixelColor(i, j) == (ji.getPixelColor(i+1,j-1))){ // compare to top right
complist[numberOfComponents].addFirst(new Pixel(i,j,numberOfComponents)); break;
}
if(ji.getPixelColor(i, j) == (ji.getPixelColor(i-1,j))){ // compare to left
complist[numberOfComponents].addFirst(new Pixel(i,j,numberOfComponents)); break;
}
} // end of if(numberOfNeighbors == 1)
Basically what I would like to do, however inefficient this may be, is compare a something 4 times, but if it turns out it is a match, break out of the set of the 4 nested if statements, as well as the outer if statement.
Will this work? or will it just break out of the nested if its currently at and continue to the next until its gone through all 4?
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