Python3: for-loop break and else (if statement)

Background information:

hey, I want to do the following: I have a dictionary with IDs as keys and lists with various things as value. One of the items of the value is a string. I want to check, if a list contains this string. And I want to do it for all keys in my dictionary.

• If the list contains the string, I want to print "String is valid"
• If the list does not contain the string, I want to print "String is NOT valid"

So far, so good.

Furthermore, the lists I want to check depend on one console input of the user, which specifies, which list should be checked. The console input is "number".

My idea was to iterate over my dictionary and my list with a nested for-loop and compare, if the string(the item of the value) is equal to any list item. If it is, I want to break out of the loop. If the String is not found in the list, I want to execute the else-statement to print my "String is not valid" message.

Code snippet:

def validationHelper(myDict, myList):
        for key in myDict:
            for value in myDict[key][0]:
                for item in myList:
                    if value==item:
                        validationHelper.true="String is valid"
                        break
                else:
                    validationHelper.true="Warning: String is NOT valid"

def validation(anyList,helperfunc):
    if anyList=="one":
        return helperfunc(finalDict,myList1)
    if anyList=="two":
         return helperfunc(finalDict,myList2)
    if anyList=="three":
         return helperfunc(finalDict,myList3)

validation(number, validationHelper)

print(validationHelper.true)

Problem:

I am running this, but no matter if the string is in the list or not, I always get my printout for the else-statement. So, I guess I have an error in reasoning in my for-loop? Or maybe, I did not understand for-loops at all?! I have tried out different indentions with the else-statement, but couldnt solve my problem.