I have a code. Somehow, it only able to pick the last hidden input name field instead of the other one. I also tried use if and else but nothing is displayed. Please advise.
Without the if else cases scenario:
HTML:
<div class="tab-label">
<input type="radio" id="ldktech_product_good" name="conditition" value="good" >
<input type="hidden" id="ldktech_product_price_good" name="price" value="7.50">
<label for="ldktech_product_good">Good</label>
NOTE: Please include the charger with your iPad trade-in, or a replacement fee will be deducted from the offer
<div class="tab-label">
<input type="radio" id="ldktech_product_flawless" name="conditition" value="flawless" >
<input type="hidden" id="ldktech_product_price_flawless" name="price" value="10">
<label for="ldktech_product_flawless">Flawless</label>
PHP:
$condition = $_POST["conditition"];
$price = $_POST["price"];
echo $price;
echo "<br>";
echo $condition;
With the if else scenarios:
HTML Code:
<div class="tab-label">
<input type="radio" id="ldktech_product_good" name="conditition" value="good" >
<input type="hidden" id="ldktech_product_price_good" name="price-good" value="7.50">
<label for="ldktech_product_good">Good</label>
<div class="tab-label">
<input type="radio" id="ldktech_product_flawless" name="conditition" value="flawless" >
<input type="hidden" id="ldktech_product_price_flawless" name="price-flawless" value="10">
<label for="ldktech_product_flawless">Flawless</label>
PHP code:
$condition = $_POST["conditition"];
if($condition == "good"){
$price = $_POST["price-good"];}
else if ($condition == "flawless"){
$price = $_POST["price-flawless"];}
echo $price;
echo "<br>";
echo $condition;
Nothing work. Please advised
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