Matching matrices of different size and creating new matrix in MATLAB

I have a matrix A and B as the following:

A = [1 NaN 3 4 5 NaN NaN 8 9 10];
B = [2 6 7];

Matrix B has the same size as there are NaN values in matrix A (so 3x1 in this case).

I would like to replace the NaN values in the same order as the values appear in B. So the output should look like:

A = [1 2 3 4 5 6 7 8 9 10];

I can replace the NaN, if both matrices have the same size. For T = 10 and N = 1, I would use:

for t=1:T
    for i=1:N
        if A == NaN
        C(t,i) = B;
        else
        C(t,i) = A(t,i);
        end
    end
end

However, I would like to know whether I could compare these matrices and replace the values even if the matrices are of different size? Saying differently, if A = NaN take the first value of B. For the next A = NaN take the second value in B.