Odd behavior of yield inside a if then block

I have a function that returns a generator or a list depending on a flag.

Yet even when I set the flag to list the function still returns a generator; also doesn't print the flag.

I expect the print statement prior to the yield command to be evaluated first. Also for that matter if the flag is set to list I do not expect the generator block to evaluate at all.

import os

def get_iterator_all_files_name(dir_path, flag):
    if flag == 'generator':
        print(flag)
        for (dirpath, dirnames, filenames) in os.walk(dir_path):
            for f in filenames:
                yield os.path.join(dirpath, f)
    elif flag == 'list':
        print(flag)
        paths = list()
        for (dirpath, dirnames, filenames) in os.walk(dir_path):
            for f in filenames:
                paths.append(os.path.join(dirpath, f))
        return paths

Using the function...

file_path = 'path/to/files'
flag = 'list'
foo = get_iterator_all_files_name(file_path, flag)
type(foo)

Which produces the result...

generator

Which is not what I expect; I was expecting list.