How to check if any row of a matrix contains all 'A's?

I've been trying to do this, but the problem is that there's always something wrong or missing with the final result. I have a lot of if statements and I wanted to see if it is possible to reduce it by using a for loop.

char matrix[3][3] = {
    {'A','A','A'},{'B','A','B'},{'C','A','C'}
};

if (matrix[0][0] == 'A' && matrix[0][1] == 'A' && matrix[0][2] == 'A') {
            cout << "Found!" << endl;
        }

There are a lot more if statements and I didn't put it here because it's the same thing just different index.

I tried to do a for loop like this,

for (int i = 0; i < matrix[0][2]; i++) {
            if (matrix[0][0] == matrix[0][1] && matrix[0][0] == matrix[0][2])
                cout << "Found!" << endl;
            break;
        }

This looks more organized compared to almost 20 lines of if statements, but it still missing some parts. For example in the array [0][1] and [1][1] and [2][1] all have the character 'A'. How can implement this into the for loop to print out the message when the same character appears in the same line vertically or horizontally.