Anyway I can shorten this IF statement?

I want the program to only print the 9 digit numbers that obey all the rules set by the IF statement. However, I feel like it is unnecessarily long and I would love it if someone could show me some syntax that would shorten it. Thanks in advance :)

EDIT: I need to figure out every single different combination of a 3x3 grid using only numbers 1,2 & 3. However, 1, 2 & 3 can only go in a single row ONCE and also go in a single column ONCE. N.b. I think there are 12 different combinations.

public static void main (String [] args){



    int count =0;

    for (int i=111111111; i<1000000000; i++){



        int X=i;
        String x= String.valueOf(X);
        String a1= x.substring(0,1);
        String a2= x.substring(1,2);
        String a3= x.substring(2,3);
        String b1= x.substring(3,4);
        String b2= x.substring(4,5);
        String b3= x.substring(5,6);
        String c1= x.substring(6, 7);
        String c2= x.substring(7,8);
        String c3= x.substring(8,9);

        int A1= Integer.parseInt(a1); 
        int A2= Integer.parseInt(a2);
        int A3= Integer.parseInt(a3);
        int B1= Integer.parseInt(b1);
        int B2= Integer.parseInt(b2);
        int B3= Integer.parseInt(b3);
        int C1= Integer.parseInt(c1); 
        int C2= Integer.parseInt(c2);
        int C3= Integer.parseInt(c3);

        if (A1+B1+C1+A2+B2+C2+A3+B3+C3==18 
            && A1<=3 && A2<=3 && A3<=3 && B1<=3 && B2<=3 && B3<=3 && C1<=3 && C2<=3 && C3<=3 
            && A1+B1+C1==6 && A1+A2+A3==6 
            && A1!=B1 && B1!=C1 && A1!=C1 && A1!=A2 && A2!=A3 && A1!=A3 && C1!=C2 && C2!=C3 
            && C1!=C3 && B1!= B2 && B1!=B3 && B2!=B3 && A3!=B3 && A2!=B2 && A3!=C3 && A2!=C2 
            && B2!=C2) 
        {             

                count++;                                                                                                        
                    System.out.println(count);
                    System.out.println(i);