if integer is greater than x but less than y (Swift)

I was wondering if there is any smooth way of checking the value of an integer in a range in swift.

I have an integer that can be any number between 0 and 1000

I want to write an if statement for "if the integer is between 300 and 700 - do this and if its any other number - do something else"

While I could write:

If integer > 300 {
    if integer < 700 {
      //do something else1
    }
    //do something
} else {
    // do something else2
                    
}

But I want to minimize the amount of code to write since "do something else1" and "do something else2" are supposed to be the same

It doesn't seem that you can write :

if 300 < integer < 700 {

} else {

}

I tried using "if integer == 300..<700 { }

but that didn't work either. Anybody got a suggestion?