First I check a given condition, as per a normal IF
statement. If it is True
, I need to scan all files for a single keyword. If it is not True
, I need to scan all files for a set of keywords, which will have been supplied.
For my simple working example, rather than scanning file names in a directory, I simply search a string for the keywords.
test1 = "NotKeyWord"
password = "password"
password1 = "password1"
password2 = "password2"
password3 = "password3"
if test1.lower() == "keyword":
condition = password
else:
condition = [password1, password2, password3]
f = "password1_password2_password3_jibberish_E=mc2"
if condition in f:
print("Problem solved")
If the keyword = "keyword" i.e., is singular, then this code works. Fine. However, I would like to make it so that if it is the other case, which requires knowing several keywords to grab the right file, I don't need to resort to explicitly writing out all the words.
For my purposes I could write
if password1 in f and password2 in f and password3 in f:
print("problem solved")
But I am after a pythonic method, that will hopefully be generic enough to be able to handle an array of keywords that is of unknown length, and thus can't be hard coded.
Aucun commentaire:
Enregistrer un commentaire