I am writing a program for 8051 which uses 2 switch to do two different commands. i.e., When switch 1 is pressed (s1==1), it execute action 1 and when switch 2 is pressed (s2==1), it executes action 2.
What I am trying to achieve here is for example, when action 1 is executing, if switch 2 is pressed, it will break action 1 and execute action 2. The same goes for the opposite case.
Below are my program codes.
#define seg P2
#define leds P3
sbit buzzer at P2_7_bit;
sbit s1 at P1_0_bit;
sbit s2 at P1_7_bit;
unsigned char pattern1[]={0x80,0x40,0x20,0x10,0x8,0x4,0x2,0x1};
unsigned char pattern2[]={0x1,0x2,0x4,0x8,0x10,0x20,0x40,0x80};
unsigned char pattern3[]={0x81,0xC3,0xE7,0xFF,0xE7,0xC3,0x81};
unsigned char pattern4[]={0x1,0x3,0x7,0xF,0x1F,0x3F,0x7F,0xFF};
unsigned char pattern5[]={0x99,0x66};
const int t1 = 600;
const int t2 = 150;
int j,k,pb1,pb2;
void main()
{
seg=0x0;
leds=0;
buzzer=0;
s1=s2=0;
while(1)
{
if(s1==1)
{
for(j=0; j<1; j++)
{
seg=0x06; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x6F; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x77; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x3F; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x6F; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x39; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x3F; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x3F; delay_ms(t1); seg=0x0; delay_ms(t2);
seg=0x06; delay_ms(t1); seg=0x0; delay_ms(t2);
}
}
if(s2==1)
{
seg=0x3F;
for(j=0; j<2; j++)
{
for(k=0; k<8; k++)
{
leds=pattern1[k]; delay_ms(250);
}
buzzer=1; delay_ms(2000);
buzzer=0;
}
for(j=0; j<3; j++)
{
for(k=0; k<8; k++)
{
leds=pattern2[k]; delay_ms(250);
}
buzzer=1; delay_ms(2000);
buzzer=0;
}
for(j=0; j<4; j++)
{
for(k=0; k<7; k++)
{
leds=pattern3[k]; delay_ms(250);
}
buzzer=1; delay_ms(2000);
buzzer=0;
}
for(j=0; j<5; j++)
{
for(k=0; k<8; k++)
{
leds=pattern4[k]; delay_ms(250);
}
buzzer=1; delay_ms(2000);
buzzer=0;
}
for(j=0; j<10; j++)
{
for(k=0; k<2; k++)
{
leds=pattern5[k]; delay_ms(250);
}
buzzer=1; delay_ms(2000);
buzzer=0;
}
seg=0x0;
leds=0x0;
}
}
}
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