Why does this program only give me output the first case of an if conditional? [duplicate]

When entering values ​​that check the states, the else if in this program does not give an output unless the condition is fulfilled in the first if condition only.

#include<stdio.h>
#include"STD_TYPES.h"
#include"REG.h"
#include"BIT_MATH.h"
#define PA 40
#define PB 63
#define PC 20
#define PD 10
 
void main (void){
    int pin ;
    
    printf("Enter The Pin Number \n");
    scanf("%d",&pin);
    if (PA<=pin<=PA+7){
        for(int i=0 ;i<=7;++i){
            if(pin==PA+i){
                printf("your are in the port A and pin %d \n",i);
                break;
            }
        }
    }else if(PB<=pin<=PB+7){
        for(int i=0 ;i<=7;++i){
            if(pin==PB+i){
                printf("your are in the port B and pin %d \n",i);
                break;
            }
        }
    }else if(PC<=pin<=PC+7){
        for(int i=0 ;i<=7;++i){
            if(pin==PC+i){
                printf("your are in the port C and pin %d \n",i);
                break;
            }   
        }
    }else if(PD<=pin<=PD+7){
        for(int i=0 ;i<=7;++i){
            if(pin==PD+i){
                printf("your are in the port D and pin %d \n",i);
                break;
            }
        }
    }
}

Note that when I use if instead of else if the program runs and gives output. What's the problem?