Floating point comparision [duplicate]

This question already has an answer here:

• Is floating point math broken? 27 answers

#include <stdio.h>
int main()
{
    float f; 
    f = 0.4;
    if(f<0.4)
       printf("It is less");
    if(f>0.4)
       printf("It is greater");
    if(f==0.4)
       printf("It is equal");
}

I am not able to get why the output is showing "It is greater".

I get that 0.4 converted to binary representation is 0x3ECCCCCD, which is 4.000000059604644775390625E-1. The doubt is if f stores this rounded value, why 0.4 in the comparison is exact. If both f and 0.4 gets rounded, the output should have been "It is equal".

I tried with f = 0.5, it is showing "It is equal".

While f=0.9, it is showing "It is less".