It repeats it twice to have the 2 tags ticked

$tagsid=mysql_query("SELECT * FROM tags WHERE image=$image_id");
while($rowtagsid=mysql_fetch_array($tagsid)) {
$tagx = $rowtagsid['tag'];  

$tagsname=mysql_query("SELECT * FROM tagnames WHERE id=$tagx");
    while($rowtagsname=mysql_fetch_array($tagsname)) {

   $codex = $rowtagsname['name'];

$options0=mysql_query("SELECT * FROM tagnames");
  while($row08=mysql_fetch_array($options0)) {
    $name08=$row08['name'];

?>

  <input name='tagchange' type='checkbox' value='<?PHP echo $name08; ?>'<?PHP if($codex==$name08) echo 'checked'; ?>><span><?PHP echo $name08; ?></span>


  <?PHP } } } ?>

The two tags in the tables are tag1 and tag5 but why does in need to copy it twice to display both and probably 3 times to diplay 3 can it not do in one single row of tags?

Here's error Just repeats it for the other tag does not do it on one line of tags crates a second!

And if I had one extra tag eg tag3 then it would display it 3 times like this

Also the error is this but I want to fix it not to delete it Heres the Error

<?PHP if($codex==$name08) echo 'checked'; ?>