Problems with [ ][ ] and if-statement

I have an error in my program, which i'll state below:

int[][]image =
    {
        {0,0,2,0,0,0,0,0,0,0,0,0},
        {0,0,0,0,0,0,0,0,0,0,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,5,5,5,5,5,5,5,5,0,0},
        {0,0,0,0,0,0,0,0,0,0,0,0},
        {0,0,0,0,0,0,0,0,0,0,0,0}//assume this rectangular image
    };  

    int[][]smooth = new int[image.length][image[0].length]; //new array equal to image[][]

Notice image[][]. It is a 2D array composed of a series of numbers. The code right below it, initializes a new 2D array called smooth[][] that is identical to image[][].

I replace each element in smooth[][] with the numerical average of the eight elements that surround it (plus the element itself) in the array. This, I have done.

However, note the elements in image[][] that are at the edge of the array. These elements are located within row 0 and column 0. Any of these edge-elements, I want to keep the same in smooth[][]. I attempt to do this with if-statements, but it doesn't work. How do I make this work?

    //compute the smoothed value of non-edge locations insmooth[][]
    for(int r=0; r<image.length-1; r++){// x-coordinate of element
    for(int c=0; c<image[r].length-1; c++){ //y-coordinate of element

    int sum1 = 0;//sum of each element's 8 bordering elements and itself

    if(r == 0 && c == 0)
        smooth[r][c] = image[r][c];     
    if(r >= 1 && c >= 1)
    {
        sum1 = image[r-1][c-1] + image[r-1][c] + image[r-1][c+1] + image[r][c-1] + image[r][c] + image[r][c+1] +image[r+1][c-1] + image[r+1][c] + image[r+1][c+1];
        smooth[r][c]= sum1 / 9; //average of considered elements becomes new elements
    }