Java Regex jumps to next match with if clause

I have this source:

 import java.util.regex.Matcher;
 import java.util.regex.Pattern;

 public class RegexStrings {

public static void main(String[] args) {
    final String EXAMPLE_TEST = "Real bad day today XY= '5678' XY='345' yes really AYB='3456' and maybe also SA='87565' or maybe this AS = '9867' or maybe even not";
    final String regex = "XY\\s*=\\s*'\\d+'";
    final Pattern pattern = Pattern.compile(regex);
    final Matcher matcher = pattern.matcher(EXAMPLE_TEST);

    System.out.println(matcher.find());

    if(matcher.find()) {

    System.out.println(matcher.group());

    String newstring=matcher.group().replaceAll("'", "");
    System.out.println(newstring);

    String finalstring=EXAMPLE_TEST.replaceAll(matcher.group(), newstring);
    System.out.println("ENDE:" + finalstring);
    }

}
}

Without the if clause it replaces XY= '5678' with XY= 5678 and all is well, with the if clause it replaces XY='345' with XY=345. But it should only replace the one it first finds.

Any idea on how to fix it?

Thanks.