Python Code Skips IF Block and execute ELSE (Program to detect if input of user matches a defined var)

I Have already gone through a similar question but that didn't help I was given this assignment to create a program that shall ask a question say what is 2+2 and will detect if the input given by the user matches the pre-declared var say, ans = 4. If the answer was correct, the program will praise the user and stop else the program will say Try Again! and let the user input again.

I made slight change for having fun :p but the thing is the MAIN PART DOES NOT WORK AS IT SHOULD. And even if I eneter the right answer the code skips to the ELSE block which would only be considered if the ans was incorrect.

Please Help me out I need to submit this tomorrow :)

My code along with images :

#Python_Maketh_Perfect

answer = 5

question =input("What is the cube root of 125? ")

if question == answer:

    print ("Good!")

else:

    trial = input("Incorrect! Try again ")
    while trial != answer:
        print ("YOu NUUUB GET NO B(.)(.)B")

enter image description here