I am having trouble using nested ifs in Netlogo to specify deer reproductive probabilities. Here is what I have come up with so far:
to reproduce-adult
let chance-fawn random-float 1.001
let chance-to-reproduce .9
let chance-for-one .3
let chance-for-two .4
let chance-for-three .02
if any? femadults [
ask femadults [
if random-float 1.001 < chance-to-reproduce [
if chance-fawn < chance-for-three
[set births (births + 3)
let new-offspring nobody
hatch-infants 3
[set new-offspring self set color red - 1 set size 1]
set offspring new-offspring]
if chance-fawn > chance-for-two
[set births (births + 2)
let new-offspring nobody
hatch-infants 2
[set new-offspring self set color red - 1 set size 1]
set offspring new-offspring]
if (chance-fawn > .02) and (chance-fawn < chance-for-one)
[set births (births + 1)
let new-offspring nobody
hatch-infants 1
[set new-offspring self set color red - 1 set size 1]
set offspring new-offspring]
]]]
end
Basically, the chance of a doe getting pregnant is 90%. So I want that if the doe gets pregnant, she either has 1, 2 or 3 fawns. The chance of having 1 fawn is 28%. The chance of having 2 fawns is 60%. The chance of having 3 fawns is 2%. The problem with my current code is that if "chance-fawn" is between .3 and .4, it is not accounted for in the if statements, when it should be part of the 60% of having 2 fawns. Is there a better way to do this, using either if statements or something else? Thank you!
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